In the majority of cases, reading (or calculating) forms the weakest link. Here is some material that can help you.
Geta--capturing in a net
Problem 1: As the white group in the corner is alive, the marked white stone splits the Black stones. How can you capture it?
Problem 2: Black needs to capture the white stones. He can't do so right away. However, with some preparation, he can. How?
Problem 3: The only way for Black to link up his stones is by trapping the marked white stone. How?
Problem 4: Black's marked stones are in trouble. However, he can ensure the capture of White's marked stones. Where should he move?
Problem 5: White's marked stones split the black formations. How can Black trap them?
Solution 1: Black 1 ensures the capture of the marked white stone. Instead of this move, Black can reach the same goal by playing at A. All other moves fail.
Solution 2: Black must force the exchange Black 1 for White 2 before playing at 3 to trap the marked white stones. If he omits the 1-for-2 exchange, White can play at A and Black can't answer at B to prevent the marked stones from escaping (White will cut at C).
Solution 3A: Black 1 is the correct move. White 2 is the strongest counter, but black 3 ensures the capture of the marked stone.
Solution 3B: White can try the strong combination of 4 and 6. While sacrificing the marked black stone, black 7 and 9 capture the marked white stone. Mission accomplished.
Solution 4A: Black 1 traps the marked white stones in a net. White can't escape with a move like A. Black cuts with B, followed by white C, black D, white E and black F. White is out of options.
Solution 4B: White 2 shows more venom. However, black 3 takes away a liberty and freedom in general. White can't escape as the sequence to 9 shows. After this move, White's stones are in atari (down to their last liberty) and he can't connect at 3 either.
Solution 5A: Black 1 captures the marked stones. After the forcing moves 6 and 8, White seems to pull off a major success by capturing with 10. However#0x85# Solution 5B: Black 11 through 15 force White to play 12, 14 and 16. Next, black 17 catches the culprits. The exchange white 18 for 19 is fruitless. White is trapped.
Caution: Problems in go books are much easier to solve than those in real games.
Semi-geta, or squeeze
Have a look at Solution 5 again. Black did trap all of White' stones, but even if he hadn't--for example, if he hadn't been able to connect at 19--the result would still be terrific for him. Black's wall is overwhelming. We often refer to these semi-geta shapes as a "squeeze."
Problem 6: Based on solutions 5A and B, can you find a good combination for Black?
Problem 7: Black has two stones clinging to White's wall. How can Black save one of them using a nice squeeze?
Problem 8: This kind of situation often happens in real life. The marked black stones are dead. How can Black squeeze the most out of their existence? Find the answers to problems 6 to 8 next week.
Want to find out more? Come to Ben's Cafe in Takadanobaba (03-3202-2445 or www.benscafe.com), where the English-speaking go community congregates every Sunday starting at 11 a.m. You can enjoy free lessons until 1 p.m.
Van Zeijst is a four-time European go champion and European representative at the Fujitsu World Championship.